Question
Question: If [.] denotes the greatest integer function. Statement 1: $\left[ \lim_{x \to 0} \frac{sin x}{x} =...
If [.] denotes the greatest integer function.
Statement 1: [limx→0xsinx=1]
Statement 2: [limx→0xsinx]=1α→limx→0[xsinx]=0

Statement-1 is True, Statement-2 is True and Statement-2 is a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is True and Statement-2 is NOT a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is False.
Statement-1 is False, Statement-2 is True.
Statement-1 is True, Statement-2 is True and Statement-2 is NOT a correct explanation for Statement-1.
Solution
Statement 1 Analysis: We know the standard limit:
x→0limxsinx=1Substituting this value into the greatest integer function:
[1]=1So, Statement 1 simplifies to 1=1, which is True.
Statement 2 Analysis: This statement comprises two parts.
Part 1: [limx→0xsinx]=1 As shown in Statement 1's analysis, limx→0xsinx=1. So, [1]=1. This part is True.
Part 2: limx→0[xsinx]=0 For x very close to 0 but not equal to 0, we know that 0<xsinx<1. Since xsinx approaches 1 from values less than 1, the greatest integer of xsinx will be 0:
[xsinx]=0for x close to 0,x=0Therefore,
x→0lim[xsinx]=0This part is True.
Assuming 'α→' signifies logical implication ("If P, then Q"), then Statement 2 is "If (True), then (True)", which makes the entire Statement 2 True.
Relationship between Statement 1 and Statement 2: Statement 2 highlights a key distinction in limits involving the greatest integer function: [limx→af(x)] is not necessarily equal to limx→a[f(x)]. While Statement 2 provides valuable context by showing this difference, it does not directly explain why Statement 1 is true. Thus, Statement 2 is NOT a correct explanation for Statement 1.