(1 + i^{2} + i^{4} + i^{6} + ..... + i^{2n})is | MATH - INTEGRAL POWER OF IOTA, ALGEBRAIC OPERATIONS AND EQUALITY OF COMPLEX NUMBERS | SolveeIt

$1 + i^{2} + i^{4} + i^{6} + ..... + i^{2n}$ is

Positive

Negative

Zero

Can not be determined

Answer

Can not be determined

Explanation

Sol. $1 + i^{2} + i^{4} + i^{6} + ..... + i^{2n} = \sum_{k = 0}^{n}{i^{2k} = 1}$ or – 1

(which is depend upon the value of n).

Question: \(1 + i^{2} + i^{4} + i^{6} + ..... + i^{2n}\)is...