Question
Question: 1 g of non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B w...
1 g of non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1: 5. The ratio of the elevation in their boiling points is ΔTb(B)ΔTb(A) , is:
A. 5 : 1
B. 10 : 1
C. 1 : 5
D. 1 : 0.2
Solution
. The relationship between ebullioscopic constants and elevation in boiling point of the solution is as follows.
(ΔTb)=(Kb)(m)
Where ΔTb = boiling temperature
Kb = Boiling point of ebullioscopic constant or boiling point
m = molality of the solution
Complete step by step answer:
- We have to find the ratio of elevation in the boiling point of the solution after adding non-volatile non electrolyte solutes to two solvents A and B.
- The amount of solute added in 100 g of solvent A is 1 g.
- The molality of solution A and Solution B is the same because they have the same solute in the same concentration in the same amount (100 g) of the solvents.
- Therefore the solutions A and B have the same molality (m).
- The elevation in boiling points of solutions A and B is as follows.
(ΔTb)B(ΔTb)A=(Kb)B(Kb)A×mBmA
- In the above formula, the molality of both the solutions A and B are the same. So, the molality is going to cancel each other out.
- In the question it is given that the ebullioscopic constants of A and B solutions are in the ratio of 1: 5.
- Therefore