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Question

Chemistry Question on Solutions

1 g of non-volatile non-electrolyte solute is dissolved in 100g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, ΔTb(A)ΔTb(B)\frac{\Delta T_b(A)}{\Delta T_b (B)}, is:

A

5:01

B

10:01

C

1:05

D

01:00.2

Answer

1:05

Explanation

Solution

ΔTb=Kb×m\Delta T_{b} = K_{b} \times m
ΔTb(A)ΔTb(B)=Kb(A)Kb(B)as  mA=mB\therefore \frac{\Delta T_{b\left(A\right)}}{\Delta T_{b\left(B\right)}} = \frac{K_{b\left(A\right)}}{K_{b\left(B\right)}} as \space m_{A} =m_{B}
ΔTb(A)ΔTb(B)=15\therefore \frac{\Delta T_{b\left(A\right)}}{\Delta T_{b\left(B\right)}} = \frac{1}{5}