Question

$1 + \frac{(\log_{e}n)^{2}}{2!} + \frac{(\log_{e}n)^{4}}{4!} + .... =$

• A. $n$
• B. $1/n$
• C. $\frac{1}{2}(n + n^{- 1})$
• D. $\frac{1}{2}(e^{n} + e^{- n})$

Answer 1

Answer: (C)

$\frac{1}{2}(n + n^{- 1})$

Answer 2

$\log_{e}2$=$\log_{e}4$.