Solveeit Logo
Login

Question

Question: \[1 + \frac{a - bx}{1!} + \frac{(a - bx)^{2}}{2!} + \frac{(a - bx)^{3}}{3!} + ....\infty =\]...

1+a−bx1!+(a−bx)22!+(a−bx)33!+....∞=1 + \frac{a - bx}{1!} + \frac{(a - bx)^{2}}{2!} + \frac{(a - bx)^{3}}{3!} + ....\infty =

A

ea−bxe^{a - bx}

B

ea−bx−1e^{a - bx} - 1

C

1+alog⁡e(a−bx)1 + a\log_{e}(a - bx)

D

e−bxe^{- bx}

Answer

ea−bxe^{a - bx}

Explanation

Solution

(1+3)log⁡e3+1+322!(log⁡e3)2+1+333!(log⁡e3)3+.....∞=(1 + 3)\log_{e}3 + \frac{1 + 3^{2}}{2!}(\log_{e}3)^{2} + \frac{1 + 3^{3}}{3!}(\log_{e}3)^{3} + .....\infty =.