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Question

Question: \[1 + \frac{1}{3!} + \frac{1}{5!} + \frac{1}{7!} + .....\infty =\]...

1+13!+15!+17!+.....=1 + \frac{1}{3!} + \frac{1}{5!} + \frac{1}{7!} + .....\infty =

A

e1e^{- 1}

B

ee

C

e+e12\frac{e + e^{- 1}}{2}

D

ee12\frac{e - e^{- 1}}{2}

Answer

ee12\frac{e - e^{- 1}}{2}

Explanation

Solution

5e5e.