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Question

Question: \[1 + \frac{1 + 3}{2!} + \frac{1 + 3 + 5}{3!} + \frac{1 + 3 + 5 + 7}{4!} + .......\infty =\]...

1+1+32!+1+3+53!+1+3+5+74!+.......=1 + \frac{1 + 3}{2!} + \frac{1 + 3 + 5}{3!} + \frac{1 + 3 + 5 + 7}{4!} + .......\infty =

A

e/2e/2

B

ee

C

2e2e

D

3e3e

Answer

2e2e

Explanation

Solution

4e4e

1x+x22!x33!+....=1 - x + \frac{x^{2}}{2!} - \frac{x^{3}}{3!} + ....\infty =

exe^{x}.