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Question

Mathematics Question on Geometric Progression

1,12,141,-\frac 12, \frac 14 …… are in G.P., then find 8th term.

A

1128\frac {1}{128}

B

164\frac {1}{64}

C

1128-\frac {1}{128}

D

164-\frac {1}{64}

Answer

1128-\frac {1}{128}

Explanation

Solution

The correct option is (C): 1128-\frac {1}{128}.