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Question

Chemistry Question on Electrochemistry

  1. Define molar conductivity of a substance and describe how for weak and strong electrolytes, molar conductivity changes with concentration of solute. How is such change explained?
  2. A voltaic cell is set up at 25°C with the following half cells:
    Ag+ (0.001 M) | Ag and Cu2+ (0.10 M) | Cu

What would be the voltage of this cell? (Eo cell = 0.46 V)

Answer

(a.) Molar conductivity is the conductivity of a solution, which contains a given number of moles of solute in 1L. The symbol for molar conductivity is lambda and the SI unit is Sm²mol⁻¹. It behaves differently for both weak and strong electrolytes.

Strong : Molar conductivity increases linearly with the square root of the concentration. But eventually reaches a limiting value ( limiting molar conductivity) at very high concentration.

Weak : Molar conductivity increases but it is less significant as compared to strong electrolyte. At lower concentration the increase in conductivity is linear and significant.

(b.) Ecell = E°cell - 0.059n\frac{0.059}{n} log [Cu2+][Ag+]2\frac{[Cu 2^{+}]}{[Ag^{+}]^{2}}

According to the question, Ecell = 0.46V, n=2, [Cu2+] = 0.1M, [Ag+] = 0.001M

Substituting the values,

Ecell=0.460.05912 log0.1(103)2E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log \frac{0.1}{(10^{-3})^{2}}
Ecell=0.460.05912 log105E_{cell}=0.46 - \frac{0.0591}{2} \text{ } log 10^{5}
Ecell=0.460.05912×5log10E_{cell}=0.46 - \frac{0.0591}{2} \times 5log 10
Ecell=0.460.14775E_{cell}=0.46 - 0.14775
Ecell=0.312VE_{cell}=0.312V