Question
Question: Consider the two curves $C_1: y^2 = 4x; C_2: x^2 + y^2 - 6x + 1 = 0$. Then,...
Consider the two curves C1:y2=4x;C2:x2+y2−6x+1=0. Then,

C1 and C2 touch each other only at one point
C1 and C2 touch each other exactly at two points
C1 and C2 intersect (but do not touch) at exactly two points
C1 and C2 neither intersect nor touch each other
C1 and C2 touch each other exactly at two points
Solution
Substitute y2=4x into the circle equation x2+y2−6x+1=0. This yields x2−2x+1=0, which has a repeated root x=1. Substituting x=1 into y2=4x gives y=±2. The potential points are (1,2) and (1,−2). Differentiating y2=4x gives dxdy=y2, and differentiating x2+y2−6x+1=0 gives dxdy=y3−x. At (1,2), both derivatives are 1. At (1,−2), both derivatives are −1. Since the derivatives match at both points, the curves touch each other at exactly two points.
