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Question: Consider the two curves $C_1: y^2 = 4x; C_2: x^2 + y^2 - 6x + 1 = 0$. Then,...

Consider the two curves C1:y2=4x;C2:x2+y26x+1=0C_1: y^2 = 4x; C_2: x^2 + y^2 - 6x + 1 = 0. Then,

A

C1C_1 and C2C_2 touch each other only at one point

B

C1C_1 and C2C_2 touch each other exactly at two points

C

C1C_1 and C2C_2 intersect (but do not touch) at exactly two points

D

C1C_1 and C2C_2 neither intersect nor touch each other

Answer

C1C_1 and C2C_2 touch each other exactly at two points

Explanation

Solution

Substitute y2=4xy^2 = 4x into the circle equation x2+y26x+1=0x^2 + y^2 - 6x + 1 = 0. This yields x22x+1=0x^2 - 2x + 1 = 0, which has a repeated root x=1x=1. Substituting x=1x=1 into y2=4xy^2=4x gives y=±2y=\pm 2. The potential points are (1,2)(1, 2) and (1,2)(1, -2). Differentiating y2=4xy^2=4x gives dydx=2y\frac{dy}{dx}=\frac{2}{y}, and differentiating x2+y26x+1=0x^2+y^2-6x+1=0 gives dydx=3xy\frac{dy}{dx}=\frac{3-x}{y}. At (1,2)(1, 2), both derivatives are 11. At (1,2)(1, -2), both derivatives are 1-1. Since the derivatives match at both points, the curves touch each other at exactly two points.