Question
Chemistry Question on Electrochemistry
1C electricity deposits
A
10.8g of Ag
B
96500g of Ag
C
electrochemical equivalent of Ag
D
half of electrochemical equivalent of Ag
Answer
electrochemical equivalent of Ag
Explanation
Solution
From Faraday's first law,
mass, w = Z ⋅ Q
when, Q = 1 C
w=Z= electrochemical ∼ quivalent.