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Question

Chemistry Question on Electrochemistry

1C1\, C electricity deposits

A

10.8g10.8\, g of AgAg

B

96500g96500\, g of AgAg

C

electrochemical equivalent of AgAg

D

half of electrochemical equivalent of AgAg

Answer

electrochemical equivalent of AgAg

Explanation

Solution

From Faraday's first law,

mass, w = Z \cdot Q

when, Q = 1 C

w=Z= w = Z = electrochemical \sim quivalent.