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Question

Physics Question on Current electricity

11 ampere current is equivalent to

A

6.25×10186.25 \times 10^{18} electrons s−1s^{-1}

B

2.25×10182.25 \times 10^{18} electrons s−1s^{-1}

C

6.25×10146.25 \times 10^{14} electrons s−1s^{-1}

D

2.25×10142.25 \times 10^{14} electrons s−1s^{-1}

Answer

6.25×10186.25 \times 10^{18} electrons s−1s^{-1}

Explanation

Solution

Q=ItQ=It also Q=ne[e=1.6×10−19 C]Q=ne \quad\left[e=1.6 \times 10^{-19}\,C\right] ∴ne=It\therefore ne=It or n=Ite=1 A×1 s1.6×10−19n=\frac{It}{e}=\frac{1\,A \times 1 \,s}{1.6 \times 10^{-19}} =6.25×1018=6.25 \times 10^{18} electrons s−1s^{-1}