Question

1 ampere current is equivalent to

• A. 6.25 × 1018 electrons s-1
• B. 2.25 × 10-18 electrons s-1
• C. 6.25 × 1014 electrons s-1
• D. 2.25 × 1014 electrons s-1

Answer 1

Answer: (A)

6.25 × 1018 electrons s-1

Answer 2

: Q = It

Also Q = ne [e = $1.6 \times 10 ^ { - 19 } \mathrm { C }$]

$\therefore$ne = It

or (;k)$\mathrm { n } = \frac { \mathrm { It } } { \mathrm { e } } = \frac { 1 \mathrm {~A} \times 1 \mathrm {~s} } { 1.6 \times 10 ^ { - 19 } }$

$= 6.25 \times 10 ^ { 18 }$ electrons