Solveeit Logo
Login

Question

Chemistry Question on Some basic concepts of chemistry

1.78 g1.78\, g of an optically active L-amino acid (A)(A) is treated with NaNO2/HClNaNO_2/HCl at 0 ∘ C0\,^\circ\,C. 448 cm3448\, cm^3 of nitrogen was at STPSTP is evolved. A sample of protein has 0.25%0.25\% of this amino acid by mass. The molar mass of the protein is

A

34,500 g mol−134,500 \,g \,mol^{-1}

B

34,600 g mol−134,600 \,g \,mol^{-1}

C

36,500 g mol−136,500 \,g \,mol ^{-1}

D

35,600 g mol−135,600\, g\, mol ^{-1}

Answer

35,600 g mol−135,600\, g\, mol ^{-1}

Explanation

Solution

From van-Siyke method for estimation of amino acids

Molar mass of L-amino acid =1.78×22400448=\frac{1.78 \times 22400}{448}
=89=89
∵\because Protein has 0.25%0.25 \% of amino acid by mass

∴\therefore Molar mass of protein =89×1000.25=\frac{89 \times 100}{0.25}
=35600 g mol−1=35600\, g\, mol ^{-1}