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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

1.575gH2C2O42H2O1.575\, g\, H _{2} C _{2} O _{4} \cdot 2 H _{2} O in 250mL250 \,mL solution makes it 0.1N0.1 \,N. H2C2O42H2OH _{2} C _{2} O _{4} \cdot 2 H _{2} O is a dihydrate organic acid.

A

If both Assertion and Reason are true and the Reason is the correct explanation of the Assertion

B

If both Assertion and Reason are true but the Reason is not the correct explanation of the Assertion

C

If Assertion is true but Reason is false

D

If both Assertion and Reason are false

Answer

If both Assertion and Reason are true but the Reason is not the correct explanation of the Assertion

Explanation

Solution

W=ENV1000W =\frac{E N V}{1000} N=1.575×100063×250 N =\frac{1.575 \times 1000}{63 \times 250} [E\left[\because E\right. of H2C2O42H2O=1262=63]\left.H _{2} C _{2} O _{4} \cdot 2 H _{2} O =\frac{126}{2}=63\right] =0.1N=0.1 \,N H2C2O42H2OH _{2} C _{2} O _{4} \cdot 2 H _{2} O is an organic acid which contains 2 molecules of water of crystallisation.