Question

1.520 g of hydroxide of a metal on ignition gave 0.995 g of its oxide. The equivalent weight of the metal is

• A. 1.52
• B. 0.995
• C. 190
• D. 9

Answer 1

Answer: (D)

9

Answer 2

$\frac{E_{hydroxide}}{E_{metal} + E_{OH}} = \frac{E_{oxide}}{E_{metal} + E_O}$
$\frac{1.520}{E + 17} = \frac{0.995}{E+8}$
or E = 9