Question

$1.5 \,g$ of $CdCl_2$ was found to contain $0.9 \,g$ of $Cd$. Calculate the atomic weight of $Cd$.

• A. 118
• B. 112
• C. 106.5
• D. 53.25

Answer 1

Answer: (C)

106.5

Answer 2

$\%$ of $Cd$ in $CdCl_2 = \frac{0.9}{1.5 \times 100}$
$= 60 \%$
Therefore , % of $Cl_2$ in $CdCl_2 = 100 - 60 = 40\%$
$\because$ 40% part $(Cl_2)$ has atomic weight
$= 2 \times 35.5 - 71.0 \%$
$\therefore 60\%$ part $(Cd)$ has atomic weight
$= \frac{71.0 \times 60}{40}$
$= 106.5$