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Question

Question: \[(1 + 3)\log_{e}3 + \frac{1 + 3^{2}}{2!}(\log_{e}3)^{2} + \frac{1 + 3^{3}}{3!}(\log_{e}3)^{3} + ......

(1+3)log⁡e3+1+322!(log⁡e3)2+1+333!(log⁡e3)3+.....∞=(1 + 3)\log_{e}3 + \frac{1 + 3^{2}}{2!}(\log_{e}3)^{2} + \frac{1 + 3^{3}}{3!}(\log_{e}3)^{3} + .....\infty =

A

28

B

30

C

25

D

0

Answer

28

Explanation

Solution

log⁡1012\log_{10}\frac{1}{2}

log⁡en!\log_{e}n!

log⁡e12\log_{e}\frac{1}{2}.