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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

1.0 g of H2 has the same number of molecules as in:

A

14 g of N2

B

18 g of H2O

C

16 g of CO

D

28 g of N2

Answer

14 g of N2

Explanation

Solution

The number of moles (n) is given by: n=mass(g)molarmass(g/mol)n = \frac{mass (g)}{molar mass (g/mol)}. The number of molecules is given by N=nNAN = nN_A, where NAN_A is Avogadro's number.
For 1.0 g of H2_2: Molar mass of H2_2 = 2.016 g/mol Moles of H2=1.0g2.016g/mol0.496_2 = \frac{1.0 g}{2.016 g/mol} \approx 0.496 mol
Number of molecules = 0.496 ×\times NAN_A
Let's check the options:
(1) 14 g of N2_2: Molar mass of N2_2 = 28 g/mol Moles of N2=14g28g/mol=0.5_2 = \frac{14 g}{28 g/mol} = 0.5 mol Number of molecules = 0.5 ×\times NAN_A
Thus, 14 g of N2_2 has approximately the same number of molecules as 1 g of H2_2.