Question
Mathematics Question on Definite Integral
∫0π (xtanx) dx/(secx + cosx) = ?
Answer
The integral of (xtanx) dx / (secx + cosx) from 0 to π is equal to 2.
∫0π (xtanx) dx/(secx + cosx) = ?
The integral of (xtanx) dx / (secx + cosx) from 0 to π is equal to 2.