Question
Mathematics Question on Circle
∫02[x2]dx∣ is equal to
A
(A) 2−2
B
(B) 2+2
C
(C) 2−1
D
(D) −2−3+5
Answer
(D) −2−3+5
Explanation
Solution
Explanation:
I=∫02[x2]dx=∫01[x2]dx+∫12[x2]dx+∫23[x2]dx+∫32[x2]dx=∫010dx+∫121dx+∫232dx+∫323dx=[x]12+[2x]23+[3x]32=2−1+23−22+6−33=5−3−2