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Question: Assertion (A) The density of hydrogen at STP is 0.09 kg m$^{-3}$ and $R = 8.31$ J mol$^{-1}$ K$^{-1}...

Assertion (A) The density of hydrogen at STP is 0.09 kg m3^{-3} and R=8.31R = 8.31 J mol1^{-1} K1^{-1}, the root mean square speed of the hydrogen molecule is 1500 ms1^{-1}.

Reason (R) At absolute zero temperature the root mean square velocity is also zero. (NCERT Pg. 250)

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is not the correct explanation of A

C

A is true but R is false

D

A is false but R is true

Answer

A is false but R is true.

Explanation

Solution

Assertion (A) Evaluation:

  • Density Calculation:

    Using the ideal gas equation ρ=PMRT\rho = \frac{PM}{RT} with P=101325 PaP = 101325 \text{ Pa}, T=273.15 KT = 273.15 \text{ K}, M=2×103 kg/molM = 2 \times 10^{-3} \text{ kg/mol}, and R=8.31 J mol1 K1R = 8.31 \text{ J mol}^{-1} \text{ K}^{-1}:

    ρ=101325×2×1038.31×273.150.0892 kg m30.09 kg m3\rho = \frac{101325 \times 2 \times 10^{-3}}{8.31 \times 273.15} \approx 0.0892 \text{ kg m}^{-3} \approx 0.09 \text{ kg m}^{-3} The density part is correct.

  • RMS Speed Calculation:

    Using the formula vrms=3RTMv_{rms} = \sqrt{\frac{3RT}{M}}:

    vrms=3×8.31×273.152×1031845.25 m/sv_{rms} = \sqrt{\frac{3 \times 8.31 \times 273.15}{2 \times 10^{-3}}} \approx 1845.25 \text{ m/s}

    The assertion states vrmsv_{rms} is 1500 m/s, which is incorrect.

  • Conclusion: Assertion (A) is False because both parts must be true for the entire assertion to be true, and the calculated vrmsv_{rms} does not match the stated value.

Reason (R) Evaluation:

  • The formula for root mean square speed is vrms=3RTMv_{rms} = \sqrt{\frac{3RT}{M}}.
  • If the temperature (T) is absolute zero (T = 0 K), then vrms=3R×0M=0v_{rms} = \sqrt{\frac{3R \times 0}{M}} = 0.
  • Therefore, Reason (R) is True.

Final Conclusion:

Assertion (A) is False, and Reason (R) is True.