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Question

Question: \(0\) is equal to....

00 is equal to.

A

−1∣z+1∣2- \frac{1}{|z + 1|^{2}}

B

∣zz+1∣.1∣z+1∣2\left| \frac{z}{z + 1} \right|.\frac{1}{|z + 1|^{2}}

C

0

D

2∣z+1∣2\frac{\sqrt{2}}{|z + 1|^{2}}

Answer

0

Explanation

Solution

arg⁡(z1zˉ2)=argz1−arg(z‾2)=argz1+argz2\arg\left( \frac{z_{1}}{{\bar{z}}_{2}} \right) = argz_{1} - arg({\overline{z}}_{2}) = argz_{1} + argz_{2}

=arg(z1.z2)= arg(z_{1}.z_{2}).