Question

$0.6 \,mL$ of acetic acid is dissolved in $1 \,L$ of water. The value of van?t Hoff factor is $1.04$ . What will be the degree of dissociation of the acetic acid?

• A. $0.01$
• B. $0.02$
• C. $0.03$
• D. $0.04$

Answer 1

Answer: (D)

$0.04$

Answer 2

$CH_3COOH {<=>}CH_3COO^- + H^+$
$\begin{matrix}\text{Before dissolution}&1&0&0\\\ \text{After dissolution}&\left(1-\alpha\right)&\alpha&\alpha\end{matrix}$
$i = (1 - \alpha) + \alpha + \alpha$
$= 1 + \alpha$
Given that $i = 1.04$
$\therefore 1.04 = 1 + \alpha$
$\alpha = 1.04 - 1$
$= 0.04$