Question

0.5 gm of an organic compound with 60%. Carbon produce ______ gm of $CO_{2}$ upon complete combustion

Answer 1

The correct answer is 1.1
Moles of Carbon = $\frac{(0.5 \times 0.6)}{12}$
Moles of $CO_{2}$ = $\frac{(0.5 \times 0.6)}{12}$
Moles of $CO_{2}$ = $\frac{(0.5 \times 0.6)}{12}\times 44$
Moles of $CO_{2}$ = $1.1 gm$