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Question

Chemistry Question on Some basic concepts of chemistry

0.5 g of an acid is neutralized by 40 cc of 0.125 N NaOH. The equivalent mass of the acid is

A

50

B

100

C

40

D

80

Answer

100

Explanation

Solution

No. of gram equivalents of NaOH
= 40×10−3×0.125=5×10−340 \times 10^{-3} \times 0.125 = 5 \times 10^{-3}
For neutralization,
No. of gram equivalents of NaOH should be equal to no. of gram equivalents of the acid.
Hence, 5×10−3=wEwt.of acid5 \times 10^{-3} = \frac{w}{E wt. of\, acid}
∴\therefore E wt. of acid =0.55×10−3=100 = \frac{0.5 }{5 \times 10^{-3}} = 100