Question
Chemistry Question on Haloalkanes and Haloarenes
0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample is
A
(A) 80.0%
B
(B) 90.0%
C
(C) 95.0%
D
(D) 75.0%
Answer
(B) 90.0%
Explanation
Solution
Explanation:
CaSO4(ag)+BaCl2(aq)→BaSO4(s)+CaCl2(ag)136gcaSO4 produces 233g BaSO 4Weight of BaSO4=0.617gMass of CaSO4 reacted =0.617×136233=0.3601gPercentage purity of CaSO4 =0.3601×1000.400=90.025