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Chemistry Question on Some basic concepts of chemistry

0.3 g of an acid is neutralised by 40 cm3cm^3 of 0.125 N NaOH. Equivalent mass of the acid is

A

60

B

45

C

30

D

63

Answer

60

Explanation

Solution

For neutralization, no. of gram equivalents of the acid should be equal to no. of gram equivalents of the base.
No. of gram equivalents of NaOH =401000=0.125 = \frac{40}{1000} = 0.125
=5×10−3= 5 \times 10^{-3}
Now, wemass of acid=5×10−3\frac{w}{emass\, of\, acid}= 5 \times 10^{-3}
∴\therefore Emass of acid = 0.35×10−3=60\frac{0.3}{5 \times 10^{-3}} = 60