Question
Question: 0.24 g of a volatile gas upon vaporisation gives 45 ml vapour at NTP. What will be the vapour densit...
0.24 g of a volatile gas upon vaporisation gives 45 ml vapour at NTP. What will be the vapour density of the substance? (density of H2 = 1)
A.95.39
B.5.973
C.95.93
D.59.73
Solution
Vapour density is the density of vapour relative to the density of hydrogen at constant temperature and pressure. Condition NTP indicates normal temperature (273 K ) and pressure (1 atm). Use the density equation related to the molar mass of gas and molar mass of H2gas.
Step by step answer:
We know that,
Molar mass = molmass
Vapour Density = molar mass of H2 gasmolar mass of gas
At NTP condition 1 mole of any gas has volume 22400ml.
Using this relation calculate the moles of gas present in 45ml.
45 ml of gas ×22400 ml1 mol gas = 0.002009 mol gas
Now, calculate the molar mass of gas using the given mass of gas and calculated moles of gas.
Mass of gas = 0.24g
Molar mass = molmass
Molar mass = 0.002009 mol0.24 g = 119.46 g/mol
So, the molar mass of the gas is 119.46 g/mol.
Now, using the molar mass of gas and molar mass of hydrogen gas calculate the vapour density of gas as follows:
Molar mass of H2 gas =2.0 g/mol
Vapour density = molar mass of H2 gasmolar mass of gas
Vapour density = 2.0 g/mol 119.46 g/mol
Vapour density = 59.73
So, the vapour density of the substance is 59.73
Thus, the correct option is (d) 59.73
Note: Vapour density is the unit less quantity. Vapour density is half of the molar mass of gas. It can also be calculated by taking the ratio of the weight of a gas to the weight of the same volume of hydrogen gas.
Weight of hydrogen gas can be calculated using the density of hydrogen gas and volume of gas. Vapour density is always measured at the constant condition of temperature and pressure.