Question

0.2 F capacitor is charge to 600 V by a battery, on removing the battery, it is connected with another parallel plate condenser of I F . The potential decreases to

• A. 100 V
• B. 120 V
• C. 300 V
• D. 600 V

Answer 1

Answer: (A)

100 V

Answer 2

By using charge conservation
$\, \, \, \, \, 0.2 \times 600 = (0.2 + 1)V$
$V = \frac {0.2 \times 600}{1.2} = 100V$