Question

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

• A. 45
• B. 53
• C. 40
• D. 63

Answer 1

Answer: (D)

63

Answer 2

Let equivalent mass be $E$ $\therefore$ g-equivalent of acid $=\frac{0.126}{E}$ $G$-equivalents of acid = $G$ equi. of base or $\frac{0.126}{E}=20\times10^{-3}\times 0.1$ or $E=\frac{0.126\times10^{3}}{20\times0.1}$ $=63$