Solveeit Logo

Question

Chemistry Question on Equilibrium

0.1(M)HCl0.1\, (M)\, HCl and 0.1(M)H2SO40.1\, (M)\, H_2SO_4 each of volume 2ml2ml are mixed and the volume is made up to 6ml6\, ml by adding 2ml2\,ml of 0.01(N)NaCl0.01\, (N)\, NaCl solution. The pHpH of the resulting mixture is

A

1.17

B

10

C

0.3

D

log2log3\log\, 2 - \log\, 3

Answer

10

Explanation

Solution

Mili moles of H+=0.1×2+0.1×2×2=0.6H^{+}=0.1 \times 2+0.1 \times 2 \times 2=0.6
Total volume in ml=6m l=6
pH=log10[H+]p H=-\log _{10}\left[H^{+}\right]
=log(0.66)=log0.1=1=-\log \left(\frac{0.6}{6}\right)=-\log 0.1=1