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Chemistry Question on Solutions

0.06% (w/v)0.06\%\, (w/v) aqueous solution of urea is isotonic with

A

0.06%0.06\% glucose solution

B

0.6%0.6\% glucose solution

C

0.01 M0.01\ M glucose solution

D

0.1 M0.1\ M glucose solution

Answer

0.01 M0.01\ M glucose solution

Explanation

Solution

0.06% (w/V)0.06 \%\,( w / V ) aqueous solution of urea =0.06100=\frac{0.06}{100}
=6×10−4 g=6 \times 10^{-4}\, g

This means that 6×10−4 g6 \times 10^{-4} \,g of urea is present in 1L1L of solution.

Molecular mass of urea

Molarity of urea solution

=w×1000M× volume (mL)=\frac{w \times 1000}{M \times \text { volume }( mL )}
=0.06×1000100×60=0.01 M=\frac{0.06 \times 1000}{100 \times 60}=0.01 \,M
∴0.01M\therefore 0.01 M glucose solution is isotonic with 0.06%0.06 \% (w/V) solution of urea.