Question

0.05 cm thick coating of silver is deposited on a plate of 0.05 m2 area. The number of silver atoms deposited on plate are _____ × 1023. (At mass Ag = 108,d = 7.9 g/cm³)

Answer 1

Step 1. Calculate the volume of silver coating:
$Volume = 0.05 \times 0.05 \times 10000 = 25 \, \text{cm}^3$

Step 2. Calculate the mass of silver deposited:
$Mass\ of silver = 25 \times 7.9 \, \text{g}$

Step 3. Calculate moles of silver atoms:
$\text{Moles of silver } = \frac{25 \times 7.9}{108}$

Step 4. Calculate the number of atoms:
$\text{Number of atoms} = \frac{25 \times 7.9}{108} \times 6.023 \times 10^{23} = 11.01 \times 10^{23}$