Question

When a 12 g mixture of carbon and sulphur is burnt in air, then a mixture of CO2 and SO2 is produced, in which the number of moles of SO2 is half that of CO2. The mass of the carbon in the mixture is :

• A. 4.08 g
• B. 5.14 g
• C. 8.74 g
• D. 1.54 g

Answer 1

Answer: (B)

5.14 g

Answer 2

(2)

(C + S) $\longrightarrow$ CO2 + SO2

$n_{SO_{2}} = \frac{n_{CO_{2}}}{2}$

Let wt. of C = x

So, wt. of S = 12 – x

$\frac{12 - x}{32} = \frac{1}{2}\left( \frac{x}{12} \right)$

x = 5.14 g.