Question

When 100g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation n(C2H4) $\rightarrow$ (-CH2-CH2-)n is :

• A. (n/2)g
• B. 100g
• C. (100/n)g
• D. 100ng

Answer 1

Answer: (B)

100g

Answer 2

(2)

By applying POAC for C atoms

moles of ethylene 2 = mole of polythene × n × 2

$\frac{100g}{28} \times 2 = \frac{wt.ofpolethene}{28 \times n} \times n \times 2$

wt. of polyethene = 100 g