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Question: > What will be the weight of CO having the same number of oxygen atoms as present in 22 g of \(CO_{2...

What will be the weight of CO having the same number of oxygen atoms as present in 22 g of CO2CO_{2}?

A

28 g

B

22 g

C

44 g

D

72 g

Answer

28 g

Explanation

Solution

(1) : No. of O atoms in CO2=2CO_{2} = 2

Molar mass of CO2=44gCO_{2} = 44g

44g1mol22g0.5mol44g \equiv 1mol \Rightarrow 22g \equiv 0.5mol

1 Mole of CO2CO_{2}contains =2×6.023×1023O= 2 \times 6.023 \times 10^{23}Oatoms

0.50.5mole of CO2=6.023×1023OCO_{2} = 6.023 \times 10^{23}Oatoms

1 mole of CO = 6.023×1023O6.023 \times 10^{23}Oatoms

Mass of 1 mole of

CO =12+16=28g12 + 16 = 28g