Question

What will be the molarity of the solution in which $0.365g$of HCl gas is dissolved in 100 mL of solution?

• A. 2 M
• B. $0.2M$
• C. 1 M
• D. $0.1M$

Answer 1

Answer: (D)

$0.1M$

Answer 2

(4) : Molecular mass of HCl $36.5$

No. of gram moles in $0.365$g of HCl

$= \frac{0.365}{36.5} = 0.01$

Volume of solution in

$L = \frac{100}{1000} = 0.1L$

Molarity$= \frac{n}{VinL} = \frac{0.01}{0.1} = 0.1M$