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Question: > What will be the molality of the solution containing \(18.25g\) HCl gas in 500 g of water?...

What will be the molality of the solution containing 18.25g18.25g HCl gas in 500 g of water?

A

0.1m0.1m

B

1 M

C

0.5m0.5m

D

1 m

Answer

1 m

Explanation

Solution

(4) : Molality (m)

=No.ofmolesofsoluteMassofsolvent(inkg)= \frac{No.ofmolesofsolute}{Massofsolvent(inkg)}

Molality = WB×1000MB×WA(ing)\frac{W_{B} \times 1000}{M_{B} \times W_{A}(ing)}

=18.25×100036.5×500= \frac{18.25 \times 1000}{36.5 \times 500} (∵MolarmassofHCl=36.5gmol−1)(\because MolarmassofHCl = 36.5gmol^{- 1})

= 1 m