Question

What weight of CaCO3 must be decomposed to produce the sufficient quantity of carbon dioxide to convert 21.2 kg of Na2CO3 completely in to NaHCO3. [Atomic mass Na = 23, Ca = 40]

CaCO3$\longrightarrow$CaO + CO2

Na2 CO3 + CO2 + H2O $\longrightarrow$2NaHCO3

• A. 100 Kg
• B. 20 Kg
• C. 120 Kg
• D. 30 Kg

Answer 1

Answer: (B)

20 Kg

Answer 2

(2)

Moles of Na2CO3$= \frac{21.2 \times 10^{3}}{106} =$ 200

So moles of CO2 = 200

& so moles of CaCO3 reqd = 200

$\therefore$ wt of CaCO3 reqd = 200 × 100 = 20 kg.