Question

What is the total number of electrons present in $1.6$g of methane?

• A. $6.023 \times 10^{23}$
• B. 16
• C. $12.04 \times 10^{23}$
• D. $6.023 \times 10^{24}$

Answer 1

Answer: (A)

$6.023 \times 10^{23}$

Answer 2

(1) : 1 mole of $CH_{4}$=16 g

$16gofCH_{4}$contain 10 electorns

1.6 g of $CH_{4}$contain $\frac{10}{16} \times 1.6 \times 6.023 \times 10^{23}$

= $6.023 \times 10^{23}$electrons