Question

What is the concentration of copper sulphate $(inmolL^{- 1})$ if 80 g of it is dissolved in enough water to make a final volume of L?

• A. $0.0167$
• B. $0.167$
• C. $1.067$
• D. $10.67$

Answer 1

Answer: (B)

$0.167$

Answer 2

(2) : Molar mass of $CuSO_{4}$ =

$63.5 + 32 + 64 = 159.5$

Moles of $CuSO_{4}$ $\frac{80.}{159.5} = 0.50$

Volume of solution = 3 L

Molarity

= $\frac{Molesofsolute}{VolumeofsolutioninL}$

$= \frac{0.50}{3} = 0.167molL^{- 1}$