Question

The weight of AgCl Precipitated when a solution containing $5.85$g of NaCl is added to a solution containing $3.4g$ of $AgNO_{3}$is

• A. 28 g
• B. $9.25g$
• C. $2.870g$
• D. 58 g

Answer 1

Answer: (C)

$2.870g$

Answer 2

(3) : $AgNO_{3} + NaCl \rightarrow AgCl + NaNO_{3}$

No. of moles of $AgNO_{3}$ = $\frac{3.4}{170} = 0.02$

No. of Moles of NaCl $= \frac{5.85}{58.5} = 0.1$

Limiting reagent = $AgNO_{3}$

1 mole of $AgNO_{3}$produces 1 mole of $AgCl$

Weight of $AgCl$Produced

= $0.2 \times 143.5 = 2.870g$