Question

The volume of water that must be added to a mixture of 250 ml of 0.6 M HCl and 750 ml of0.2 M HCl to obtain 0.25 M solution of HCl is :

• A. 750 ml
• B. 100 ml
• C. 200 m$\mathcal{l}$
• D. 300 m$\mathcal{l}$

Answer 1

Answer: (C)

200 m$\mathcal{l}$

Answer 2

(3)

. $M_{final} = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2} + V_{water}};0.25 = \frac{0.6 \times 250 + 0.2 \times 750}{250 + 750 + V_{water}};SoV_{water} = 200ml$