Question

The number of oxygen present in 1 mole of oxalic acid dehydrate is.

• A. $6 \times 10^{23}$
• B. $6.022 \times 10^{34}$
• C. $7.22 \times 10^{23}$
• D. $36.13 \times 10^{23}$

Answer 1

Answer: (D)

$36.13 \times 10^{23}$

Answer 2

(4) : One molecule of oxalic acid dehydrate $(COOH)_{2}2H_{2}O$contains 6 oxygen atoms.

Number of oxygen atoms in 1 mole

=$6 \times 6.023 \times 10^{23}$=$36.13 \times 10^{23}$atoms