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Question: > The molarity of ClÆ in an aqueous solution which was (w/V) 2% NaCl, 4% CaCI2 and 6% NH4Cl will be...

The molarity of ClÆ in an aqueous solution which was (w/V) 2% NaCl, 4% CaCI2 and 6% NH4Cl will be

A

0.342

B

0.721

C

1.12

D

2.18

Answer

2.18

Explanation

Solution

(4)

Moles of Cl– in 100 ml of solution

=258.5+4111×2+653.5= \frac{2}{58.5} + \frac{4}{111} \times 2 + \frac{6}{53.5}= 0.2184

Molarity of Cl– =0.2184100× 1000 = 2.184.= \frac{0.2184}{100}\text{×}\text{ 1000 = 2.184.}