Question

The force of repulsion between two point charges is F, when they are d distance apart. If the point charges are replaced by conducting spheres each of radius r and the charges remain same. The separation between the centre of sphere is d, then force of repulsion between them is

• A. Equal to F
• B. Less than F
• C. Greater than F
• D. Cannot be said

Answer 1

Answer: (A)

Equal to F

Answer 2

When point charges are replaced by conducting spheres of the same radius and charge, and the distance between their centers remains the same, the force of repulsion is considered to be equal to the original force. This is because, in this simplified model, the charges are assumed to be concentrated at the centers of the spheres. The formula for the force between two charges $q_1$ and $q_2$ separated by a distance $d$ is given by Coulomb's Law: $F = k \frac{q_1 q_2}{d^2}$. If the charges and the distance between the centers remain the same, the force also remains the same.