Question

The empirical formula of a compound is $CH_{2}O_{2}$. What could be its molecular formula?

• A. $C_{2}H_{2}O_{2}$
• B. $C_{2}H_{2}O_{4}$
• C. $C_{2}H_{4}O_{4}$
• D. $CH_{4}O_{4}$

Answer 1

Answer: (C)

$C_{2}H_{4}O_{4}$

Answer 2

(3) Since empirical formula is multiplied by n to get molecular formula.

$CH_{2}O_{2}$will give only $C_{2}H_{4}O_{4}$as its molecular formula.

$(CH_{2}O_{2})_{n}$where n= 1, 2, 3, ……etc.