Question

The empirical formula and molecular mass of a compound are $CH_{2}O$and 180 g respectively. What will be the molecular formula of the compound?

• A. $C_{9}H_{18}O_{9}$
• B. $CH_{2}O$
• C. $C_{6}H_{12}O_{6}$
• D. $C_{2}H_{4}O_{2}$

Answer 1

Answer: (C)

$C_{6}H_{12}O_{6}$

Answer 2

(3) :

$n = \frac{Molecularmass}{Empiricalformulamass} = \frac{180}{30} = 6\because EmpiricalformulamassofCH_{2}O = 30)$

$\therefore$Molecular formula

$= 6 \times CH_{2}O = C_{6}H_{12}O_{6}$